Julian Seward f9d4a371e1 Merge patch from JeremyF:
75-simple-jle

Another pattern to test for Jle/Jnle. The observation is that EFLAGS
looks like this:

----O--+SZ------

with Z in bit 6, S in 7 and O in 11. Therefore RORL $7, %eflags will
result in:

Z------+-------+-------+---O---S

Since parity is only computed on the lower 8 bits, testing on P will
determine whether O==S, and since Z is in the MSB, it can be tested
with S.


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